document.write( "Question 418940: One number is 3 less than a second number. Twice the second number is 48 more than 5 times the first. Find the two numbers \n" ); document.write( "
Algebra.Com's Answer #293092 by algebrahouse.com(1659)\"\" \"About 
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\"One number is 3 less than a second number. Twice the second number is 48 more than 5 times the first. Find the two numbers\"\r
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\n" ); document.write( "\n" ); document.write( "x = second number
\n" ); document.write( "x - 3 = one number {one number is 3 less than the second}\r
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\n" ); document.write( "\n" ); document.write( "2x = 5(x - 3) + 48 {twice second is 48 more than 5 times first}
\n" ); document.write( "2x = 5x - 15 + 48 {used distributive property}
\n" ); document.write( "2x = 5x + 33 {combined like terms}
\n" ); document.write( "-3x = 33 {subtracted 5x from both sides}
\n" ); document.write( "x = -11 {divided both sides by -3}
\n" ); document.write( "x - 3 = -14 {substituted -11, in for x, into x - 3}\r
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\n" ); document.write( "\n" ); document.write( "one number is -14
\n" ); document.write( "second number is -11
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