document.write( "Question 44395: two cyclist start biking from a trail's start 3 hours apart. the second cylist travels at 10 mph and starts 3 hours after the first cyclist who is traveling at 6 mph. \n" ); document.write( "
Algebra.Com's Answer #29308 by adamchapman(301)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We know that speed is eqaul to distance divided by time: \n" ); document.write( "so \n" ); document.write( "We also know that when the second cyclist starts, the first has been travelling for three hours, so \n" ); document.write( "When the second cyclist catches up with th first, the distance travelled by each cyclist is the same: \n" ); document.write( "We are looking to find \n" ); document.write( "\n" ); document.write( "From the working, we can deduce: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So 4.5 hours will pass before the second cyclist catches up with the first from the time when the second cyclist started biking.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I hope this helps. \n" ); document.write( "P.S. I am trying to start up my own homework help website. I would be extremely grateful if you would e-mail me some feedback on the help you received to adam.chapman@student.manchester.ac.uk\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |