document.write( "Question 44394: how many liters of a 90% acid solution must be added to 6 liters of a 15% acid solution to obtain a 40% acid solution ?
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Algebra.Com's Answer #29307 by adamchapman(301) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let the amount of litres of 90% acid solution be called \"x\".
\n" ); document.write( "We know the finalsolution will have a 40% acid solution and will be 6+x litres in volume.
\n" ); document.write( "Multiplying volumes by solutions, where the percentage of acid concentration is in decimal form (i.e. 0.5=50%):
\n" ); document.write( " $\"0.9x%2B0.15%286%29=0.4%286%2Bx%29\"$
\n" ); document.write( "Now rearrange to get x:
\n" ); document.write( " $\"0.9x%2B0.9=2.4%2B0.4x\"$
\n" ); document.write( " $\"0.9x-0.4x=2.4-0.9\"$
\n" ); document.write( " $\"0.5x=1.5\"$
\n" ); document.write( " $\"x=1.5%2F0.5\"$
\n" ); document.write( " $\"x=3\"$
\n" ); document.write( "So 3 liters of a 90% acid solution must be added to 6 liters of a 15% acid solution to obtain a 40% acid solution.\r
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\n" ); document.write( "\n" ); document.write( "I hope this helps.
\n" ); document.write( "P.S. I am trying to start up my own homework help website. I would be extremely grateful if you would e-mail me some feedback on the help you received to adam.chapman@student.manchester.ac.uk
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