document.write( "Question 418849: Can someone help me please?? Thank You!!
\n" ); document.write( "20) H ow many different sequences of 4 digits are possible if the first digit
\n" ); document.write( "must be 3, 4, or 5 and if the sequence may not end in 000? Repetition of
\n" ); document.write( "digits is allowed.\r
\n" ); document.write( "\n" ); document.write( "A) 2 ,997
\n" ); document.write( "B) 2 ,999
\n" ); document.write( "C) 2 ,000
\n" ); document.write( "D) 1 ,512
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Algebra.Com's Answer #293031 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
I would compute all the possibilities as if there
\n" ); document.write( "were no restrictions. Then I would subtract the
\n" ); document.write( "choices that are not allowed
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\n" ); document.write( "With no restrictions:
\n" ); document.write( "\"+10%2A10%2A10%2A10+=+10%5E4+\"
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\n" ); document.write( "0,1,2,6,7,8, and 9 are not allowed
\n" ); document.write( "for the 1st digit. That is
\n" ); document.write( "\"+7%2A10+%2A10+%2A10++=+7%2A10%5E3\" not allowed
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\n" ); document.write( "With the last 3 digits 0,
\n" ); document.write( "\"+10%2A1+=+10\" not allowed
\n" ); document.write( "\"10%5E4+-+7%2A10%5E3+-+10+=+3000+-+10+\"
\n" ); document.write( "\"+3000+-+10+=+2990+\"
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\n" ); document.write( "Now the tricky part: When I tested for sequences not allowed
\n" ); document.write( "did I count some things twice ? If I did, I have to add those back in.
\n" ); document.write( "The \"+7%2A10+%2A10+%2A10++=+7%2A10%5E3\" not allowed includes
\n" ); document.write( "0000, 1000, 2000, 6000, 7000, 8000, and 9000
\n" ); document.write( "so, I must add these back in
\n" ); document.write( "\"+2990+%2B+7+=+2997+\" answer\r
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