document.write( "Question 44371: 
I need to know the radius and center for this \r\n" );
document.write( "equation. It is for circles: \r\n" );
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document.write( "256x² + 256y² = 64

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Algebra.Com's Answer #29303 by AnlytcPhil(1806)\"\" \"About 
You can put this solution on YOUR website!
I need to know the radius and center for this \r\n" );
document.write( "equation. It is for circles. \r\n" );
document.write( "256x² + 256y² = 64.\r\n" );
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document.write( "The equation of a circle is\r\n" );
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document.write( "(x - h)² + (y - k)² = r²\r\n" );
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document.write( "where the center is (h,k) and the radius is r.\r\n" );
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document.write( "      256x² + 256y² = 64\r\n" );
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document.write( "Divide thru by 256\r\n" );
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document.write( "    256x²     256y²     64\r\n" );
document.write( "   ------- + ------ = -----\r\n" );
document.write( "     256       256     256\r\n" );
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document.write( "     1         1         1\r\n" );
document.write( "    256x²     256y²     64\r\n" );
document.write( "   ------- + ------ = -----\r\n" );
document.write( "     256       256     256\r\n" );
document.write( "      1         1       4\r\n" );
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document.write( "            x² + y² = 1/4\r\n" );
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document.write( "Write x as (x - 0) and y as (y - 0)\r\n" );
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document.write( "(x - 0)² + (y - 0)² = 1/4\r\n" );
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document.write( "Compare to\r\n" );
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document.write( "(x - h)² + (y - k)² = r²\r\n" );
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document.write( "so h = 0, k = 0, r² = 1/4, so r = 1/2\r\n" );
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document.write( "Center = (h, k) = (0, 0), radius = 1/2\r\n" );
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document.write( "Edwin\r\n" );
document.write( "AnlytcPhil@aol.com
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