document.write( "Question 44366: elimination method\r
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document.write( "3a-12b=9
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document.write( "14a-11b=5 \n" );
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Algebra.Com's Answer #29302 by AnlytcPhil(1807) You can put this solution on YOUR website! \r\n" ); document.write( " 3a - 12b = 9\r\n" ); document.write( "14a - 11b = 5\r\n" ); document.write( "\r\n" ); document.write( "To eliminate a. The LCM of 3 and 14 is 42.\r\n" ); document.write( "Multiply the first equation thru by 14,\r\n" ); document.write( "and the second equation by -3\r\n" ); document.write( "\r\n" ); document.write( "14[ 3a - 12b = 9]\r\n" ); document.write( "-3[14a - 11b = 5]\r\n" ); document.write( "\r\n" ); document.write( " 42a - 168b = 126\r\n" ); document.write( " -42a + 33b = -15\r\n" ); document.write( " -------------------\r\n" ); document.write( " -135b = 111\r\n" ); document.write( " b = 111/(-135) \r\n" ); document.write( " b = -37/45\r\n" ); document.write( "\r\n" ); document.write( "Since -37/45 will be hard to substitute into\r\n" ); document.write( "one of the equations, we start over and\r\n" ); document.write( "eliminate b:\r\n" ); document.write( "\r\n" ); document.write( "The LCM of 12 and 11 is 132.\r\n" ); document.write( "Multiply the first equation thru by 11,\r\n" ); document.write( "and the second equation by -12\r\n" ); document.write( "\r\n" ); document.write( " 11[ 3a - 12b = 9]\r\n" ); document.write( "-12[14a - 11b = 5]\r\n" ); document.write( "\r\n" ); document.write( " 33a - 132b = 99\r\n" ); document.write( " -168a + 132b = -60\r\n" ); document.write( " -------------------\r\n" ); document.write( " -135a = 39\r\n" ); document.write( " a = 39/(-135) \r\n" ); document.write( " a = -13/45\r\n" ); document.write( " \r\n" ); document.write( " a = -13/45 b = -37/45\r\n" ); document.write( "\r\n" ); document.write( "(a, b) = (-13/45, -37/45) \r\n" ); document.write( "\r\n" ); document.write( "Edwin\r\n" ); document.write( "AnlytcPhil@aol.com\n" ); document.write( " |