document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=5688>Question 5688</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 240 inches. The length is twice it's width. find the dimensions of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2930 by </B><A HREF=/tutors/aboutme.mpl?userid=prince_abubu><B>prince_abubu(198)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=prince_abubu><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2930\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's start with Perimeter Formula for a rectangle: P = 2L + 2W.\r<BR>\n" );
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document.write( "They told us that the perimeter is 240, so 2L + 2W = 240.\r<BR>\n" );
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document.write( "\"The length is twice the width.\" Since the length is obviously longer as mentioned, we need to double the (shorter) width to equal the length, so L = 2W\r<BR>\n" );
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document.write( "Substitute 2W for L in the perimeter equation so that you'll only be solving for 1 unknown variable. 2(2W) + 2W = 240.\r<BR>\n" );
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document.write( "4W + 2W = 240\r<BR>\n" );
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document.write( "6W = 240\r<BR>\n" );
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document.write( "W = 40 inches.\r<BR>\n" );
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document.write( "We've got to find the length now. Since the length is double the width, the length would be 80 inches.\r<BR>\n" );
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document.write( "So the dimensions would be Width = 40 inches and Length = 80 inches. </SPAN>\n" );
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