document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=418731>Question 418731</A>: <I><SPAN STYLE=\"word-break: break-all;\"> keil is going to make 14 pounds of mixed nuts for a party. Peanuts cost 3.50 per pound and cashews cost 7.50 per pound.  If Keil can spend 81.00$ on nuts, how many pounds of each should he buy? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #292987 by </B><A HREF=/tutors/aboutme.mpl?userid=MRperkins><B>MRperkins(300)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MRperkins><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MRperkins><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=292987\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I can work this one at http://vyew.com/room#/365877/algebra.com if you want or you can wait and I'll answer it shortly through here.\r<BR>\n" );
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document.write( "let x=pounds of peanuts<BR>\n" );
document.write( "y=pounds of cashews\r<BR>\n" );
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document.write( "then x+y=14 since they have to add up to be 14 pounds.<BR>\n" );
document.write( "3.50x+7.50y=81\r<BR>\n" );
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document.write( "Now solve using substitution or elimination.  Substitution is likely easier in this case.<BR>\n" );
document.write( "x=14-y<BR>\n" );
document.write( "3.50(14-y)+7.50y=81<BR>\n" );
document.write( "49-3.5y+7.5y=81<BR>\n" );
document.write( "49+4y=81<BR>\n" );
document.write( "4y=32<BR>\n" );
document.write( "y=8 pounds<BR>\n" );
document.write( "x+y=14<BR>\n" );
document.write( "x+8=14<BR>\n" );
document.write( "x=6 pounds<BR>\n" );
document.write( "so he should buy 6 pounds of peanuts and 8 pounds of cashews. </SPAN>\n" );
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