document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=418577>Question 418577</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the measure of an angle such the difference between the measure of its supplement and 3 times the measure of the complement is 16 degrees </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #292884 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=292884\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the measure of an angle such the difference between the measure of its supplement and 3 times the measure of the complement is 16 degrees<BR>\n" );
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document.write( "angle: x<BR>\n" );
document.write( "complement: 90-x<BR>\n" );
document.write( "supplement: 180-x<BR>\n" );
document.write( "--------------------------<BR>\n" );
document.write( "Equations:<BR>\n" );
document.write( "180-x -(3(90-x)) = 16<BR>\n" );
document.write( "180-x -270+3x = 16<BR>\n" );
document.write( "2x - 90 = 16<BR>\n" );
document.write( "2x = 106<BR>\n" );
document.write( "x = 53 degrees<BR>\n" );
document.write( "===================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "================= </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );