document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=418430>Question 418430</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the given zero to find all the zeros of the function <BR>\n" );
document.write( "g(x)=x^3-7x^2-x+87     zero: 5+2i </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #292816 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=292816\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If 5 + 2i is a zero, then 5 - 2i must also be a zero.  Let r be the third zero.\r<BR>\n" );
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document.write( "Then from algebra, the sum of the roots of the polynomial taken one at a time is equal to <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-%28-7%29%2F1+=+7 ALIGN=MIDDLE  ALT=\"-%28-7%29%2F1+=+7\"   DISABLED_style= \"max-width:90%; height:auto;\" >, so that r + (5 + 2i) + (5 - 2i) = 7, or r + 10 = 7, or r = -3.  Therefore the zeros of the polynomial are -3,  5 + 2i, and  5 - 2i. </SPAN>\n" );
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