document.write( "Question 418432: Find three consecutive even integers such that twice the first minus three times the second plus five times the third is 54. \n" ); document.write( "
Algebra.Com's Answer #292795 by algebrahouse.com(1659)\"\" \"About 
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\"Find three consecutive even integers such that twice the first minus three times the second plus five times the third is 54.\"\r
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\n" ); document.write( "\n" ); document.write( "x = 1st consecutive even integer
\n" ); document.write( "x + 2 = 2nd consecutive even integer
\n" ); document.write( "x + 4 = 3rd consecutive even integer\r
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\n" ); document.write( "\n" ); document.write( "2x = \"twice the first\"
\n" ); document.write( "3(x + 2) = \"three times the second\"
\n" ); document.write( "5(x + 4) = \"five times the third\"\r
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\n" ); document.write( "\n" ); document.write( "2x - 3(x + 2) + 5(x + 4) = 54
\n" ); document.write( "2x - 3x - 6 + 5x + 20 = 54 {used distributive property}
\n" ); document.write( "4x + 14 = 54 {combined like terms}
\n" ); document.write( "4x = 40 {subtracted 14 from both sides}
\n" ); document.write( "x = 10 {divided both sides by 4}
\n" ); document.write( "x + 2 = 12 {substituted 10, in for x, into x + 2}
\n" ); document.write( "x + 4 = 14 {substituted 10, in for x, into x + 4}\r
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\n" ); document.write( "\n" ); document.write( "10, 12,and 14 are the three consecutive even integers
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