document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=44242>Question 44242</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1 over 2x-7 + 3 over 7-2x\r<BR>\n" );
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document.write( "show work<BR>\n" );
document.write( "isn't the bottom denominators the same? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #29275 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=29275\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> No they are not, but close, because 2x-7 / 7-2x = -1<BR>\n" );
document.write( "I posted this solution about an hour ago... </SPAN>\n" );
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