document.write( "Question 418179: How many odd 6-digit pin numbers can be made from the digits 0-9? \n" ); document.write( "
Algebra.Com's Answer #292719 by josmiceli(19441)\"\" \"About 
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There are 10 choices for the 1st digit (0-9)
\n" ); document.write( "There are 10 choices for the 2nd digit (0-9)
\n" ); document.write( "There are 10 choices for the 3rd digit (0-9)
\n" ); document.write( "There are 10 choices for the 4th digit (0-9)
\n" ); document.write( "There are 10 choices for the 5th digit (0-9)
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\n" ); document.write( "So far, there are
\n" ); document.write( "\"10%2A10%2A10%2A10%2A10+=+10%5E5\" possible pin numbers
\n" ); document.write( "This must be multiplied by the number of
\n" ); document.write( "possible choices for the final digit which must be odd
\n" ); document.write( "It can't be 0 since the pin # would be even
\n" ); document.write( "It can be 1, 3, 5, 7, or 9
\n" ); document.write( "That is 5 choices, so there are
\n" ); document.write( "5*10^5 possible 6-digit odd pin #'s
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