document.write( "Question 418179: How many odd 6-digit pin numbers can be made from the digits 0-9? \n" ); document.write( "
Algebra.Com's Answer #292719 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! There are 10 choices for the 1st digit (0-9) \n" ); document.write( "There are 10 choices for the 2nd digit (0-9) \n" ); document.write( "There are 10 choices for the 3rd digit (0-9) \n" ); document.write( "There are 10 choices for the 4th digit (0-9) \n" ); document.write( "There are 10 choices for the 5th digit (0-9) \n" ); document.write( "-------------- \n" ); document.write( "So far, there are \n" ); document.write( " \n" ); document.write( "This must be multiplied by the number of \n" ); document.write( "possible choices for the final digit which must be odd \n" ); document.write( "It can't be 0 since the pin # would be even \n" ); document.write( "It can be 1, 3, 5, 7, or 9 \n" ); document.write( "That is 5 choices, so there are \n" ); document.write( "5*10^5 possible 6-digit odd pin #'s \n" ); document.write( " |