document.write( "Question 418106: the length of a rectangle is 2 inches longer than the width of the rectangle. If the perimeter of the rectangle is 46 inches, what is the area of the rectangle? \n" ); document.write( "

Algebra.Com's Answer #292686 by ewatrrr(24785) $\"\"$ $\"About$

You can put this solution on YOUR website!


\n" );
document.write( "Hi
\n" );
document.write( "length of a rectangle is 2 inches longer than the width of the rectangle
\n" );
document.write( "Let x and (x+2) represent the width and length respectively
\n" );
document.write( "  2(x+2) + 2x = 46in
\n" );
document.write( "      4x = 42in
\n" );
document.write( "       x = 10.5in, the width.  The length is 12.5in  (10.5 + 2)
\n" );
document.write( "CHECKING our Answer***
\n" );
document.write( "  2*12.5in + 2*10.5in = 25in + 21in = 46in    
\n" );
document.write( "
\n" );
document.write( " \n" );
document.write( "

\n" );