document.write( "Question 418024: a father is now twice as old as his daughter. Ten years ago he was three times as old as she was. How old are they both now?
\n" ); document.write( "How do you work this out? What would the equation be?
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Algebra.Com's Answer #292639 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( "a father is now twice as old as his daughter
\n" ); document.write( "Let x and 2x represent the daughter's and father's ages NOW reszpectively
\n" ); document.write( "Question states*** 10 years ago...
\n" ); document.write( " 2x-10 = 3(x-10)
\n" ); document.write( "Solving for x
\n" ); document.write( " 20 = x, daughters age now. Father is 40.\r
\n" ); document.write( "\n" ); document.write( "CHECKING our Answer***10 years ago...
\n" ); document.write( " 30 = 3*10 \n" ); document.write( "
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