document.write( "Question 417941: Trains A and B are traveling in the same direction on parallel tracks. Train A
\n" ); document.write( "is traveling 60 miles per hour and train B is traveling at 80 miles per hour.
\n" ); document.write( "Train A passes a station at 6:10 P.M.. If train B passes the same station at
\n" ); document.write( "6:22 P.M., at what time will train B catch up to train A?\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #292608 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
Train A speed 60mph
\n" ); document.write( "Train B speed 80mph
\n" ); document.write( "
\n" ); document.write( "Train A passes station at 06:10
\n" ); document.write( "Train B passes station at 06:22
\n" ); document.write( "
\n" ); document.write( "Difference in time=00:12 12minutes
\n" ); document.write( "Train A will have covered 12miles before Train B starts
\n" ); document.write( "
\n" ); document.write( "catch up distance=12 miles
\n" ); document.write( "catch up speed =80-60 mph
\n" ); document.write( "catch up speed =20mph
\n" ); document.write( "
\n" ); document.write( "Catchup time = catchup distance/catch up speed
\n" ); document.write( "catch up time= 12/20
\n" ); document.write( "catch up time= 0.6 hours
\n" ); document.write( "catch up time= 36 minutes
\n" ); document.write( "Add this to 6.22 = 6.58 pm
\n" ); document.write( "
\n" );