document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=418015>Question 418015</A>: <I><SPAN STYLE=\"word-break: break-all;\"> f of g(x) and g of f(x)where f(x)=x2 the x is supposed to be squared and g(x)= x-3 next part of same problem is the domain of f of g and the domain of g of f </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #292590 by </B><A HREF=/tutors/aboutme.mpl?userid=tinbar><B>tinbar(133)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tinbar><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=292590\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f(g(x)) = f(x-3) = (x-3)^2 = x^2-6x+9<BR>\n" );
document.write( "g(f(x)) = g(x^2) = (x^2)-3\r<BR>\n" );
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document.write( "domain for f(g(x)): First we need the domain for g(x) which is all Real numbers since we can subtract 3 from any x in R(set of Real Numbers). Next, out of all these numbers, we can square any of them, therefore the domain of f(g(x)) is the entire set of Real numbers\r<BR>\n" );
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document.write( "domain for g(f(x)): Similar argument as the first one, resulting in the same domain </SPAN>\n" );
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