document.write( "Question 417857: Twice the first number is eleven more than the sum of the other two numbers. The sum of twice the first number and three times the third number is one more than the second number. The second number is equal to the sum of the first number and the third number. what are the 3 numbers? \n" ); document.write( "
Algebra.Com's Answer #292525 by mananth(16946)\"\" \"About 
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let the numbers be x, y, z\r
\n" ); document.write( "\n" ); document.write( "2x=y+z+11
\n" ); document.write( "2x-y-z=11\r
\n" ); document.write( "\n" ); document.write( "2x+3z=y+1
\n" ); document.write( "2x-y+3z=1\r
\n" ); document.write( "\n" ); document.write( "y=x+z
\n" ); document.write( "-x+y-z=0\r
\n" ); document.write( "\n" ); document.write( "2x-y-z=11-------------- 1
\n" ); document.write( "2x-y+3z =1--------------2
\n" ); document.write( "-x+y-z= 0-------------- 3
\n" ); document.write( "
\n" ); document.write( "consider equation 1 &2
\n" ); document.write( "Multiply 1 by -1
\n" ); document.write( "Multiply 2 by 1
\n" ); document.write( "we get
\n" ); document.write( "-2x+y+z =-11
\n" ); document.write( "2x-y+3z =1
\n" ); document.write( "Add the two
\n" ); document.write( "4z=-10 -------------4
\n" ); document.write( "z==-2.5
\n" ); document.write( "consider equation 2 & 3
\n" ); document.write( "Multiply 2 by 1
\n" ); document.write( "Multiply 3 by 1
\n" ); document.write( " we get
\n" ); document.write( "2x-y+3z =1
\n" ); document.write( "-x+y+-z =0
\n" ); document.write( " Add the two
\n" ); document.write( "1x+2z= 1-------------5
\n" ); document.write( "plug value of z
\n" ); document.write( "x-5=1
\n" ); document.write( "x=6
\n" ); document.write( "plug value of x & z in 1\r
\n" ); document.write( "\n" ); document.write( "12-y+2.5=11
\n" ); document.write( "y=3.5
\n" ); document.write( " \n" ); document.write( "
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