document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=417730>Question 417730</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Will solve the equation.  Just need help utilizing proper formula.  Thank you.  How many gallons of a 3% salt solution must be mixed with 50 gallons of a 7% solution to obtain a 5% solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #292418 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=292418\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> percent	----------------quantity		<BR>\n" );
document.write( "7	----------------50<BR>\n" );
document.write( "3	----------------x<BR>\n" );
document.write( "5	----------------50+x\r<BR>\n" );
document.write( "\n" );
document.write( "..<BR>\n" );
document.write( "7*50+3*x=5(50+x)<BR>\n" );
document.write( "350+3x=250+5x					<BR>\n" );
document.write( "3x-5x=250-350					<BR>\n" );
document.write( "-2x=-100<BR>\n" );
document.write( "/-2									<BR>\n" );
document.write( "x=50 gallons										<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );