document.write( "Question 417652: If you increase the numerator if by 3 and the denominator by 4, the value of the fraction will be doubled. The denominator of the original fraction is 1 more than the numerator. Find the original fraction. \n" ); document.write( "
Algebra.Com's Answer #292383 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! If you increase the numerator if by 3 and the denominator by 4, the value of the fraction will be doubled. The denominator of the original fraction is 1 more than the numerator. Find the original fraction. \n" ); document.write( "------ \n" ); document.write( "Let the original fraction be x/y \n" ); document.write( "---------------------------- \n" ); document.write( "Equations: \n" ); document.write( "(x+3)/(y+4) = 2(x/y) \n" ); document.write( "y = x+1 \n" ); document.write( "---- \n" ); document.write( "Substitute for \"y\" and solve for \"x\": \n" ); document.write( "(x+3)/(x+5) = 2(x/(x+1)) \n" ); document.write( "---------------------------- \n" ); document.write( "Cross-multiply: \n" ); document.write( "(x+3)(x+1) = (x+5)(2x) \n" ); document.write( "--- \n" ); document.write( "x^2+4x+3 = 2x^2+10x \n" ); document.write( "x^2+6x-3 = 0 \n" ); document.write( "---- \n" ); document.write( "x = [-6 +- sqrt(36-4*1*-3)]/2 \n" ); document.write( "----- \n" ); document.write( "x = [-6 +- sqrt(48)]/2 \n" ); document.write( "----- \n" ); document.write( "x = [-6 +- 4sqrt(3)]/2 \n" ); document.write( "----- \n" ); document.write( "x = -3+2sqrt(3) \n" ); document.write( "--- \n" ); document.write( "Solve for \"y\": \n" ); document.write( "y = x+1 \n" ); document.write( "y = -2+2sqrt(3) \n" ); document.write( "----- \n" ); document.write( "I doubt that is the answer you are looking for \n" ); document.write( "but that is what your post implies. \n" ); document.write( "=================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |