document.write( "Question 417652: If you increase the numerator if by 3 and the denominator by 4, the value of the fraction will be doubled. The denominator of the original fraction is 1 more than the numerator. Find the original fraction. \n" ); document.write( "
Algebra.Com's Answer #292383 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
If you increase the numerator if by 3 and the denominator by 4, the value of the fraction will be doubled. The denominator of the original fraction is 1 more than the numerator. Find the original fraction.
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\n" ); document.write( "Let the original fraction be x/y
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\n" ); document.write( "Equations:
\n" ); document.write( "(x+3)/(y+4) = 2(x/y)
\n" ); document.write( "y = x+1
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\n" ); document.write( "Substitute for \"y\" and solve for \"x\":
\n" ); document.write( "(x+3)/(x+5) = 2(x/(x+1))
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\n" ); document.write( "Cross-multiply:
\n" ); document.write( "(x+3)(x+1) = (x+5)(2x)
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\n" ); document.write( "x^2+4x+3 = 2x^2+10x
\n" ); document.write( "x^2+6x-3 = 0
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\n" ); document.write( "x = [-6 +- sqrt(36-4*1*-3)]/2
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\n" ); document.write( "x = [-6 +- sqrt(48)]/2
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\n" ); document.write( "x = [-6 +- 4sqrt(3)]/2
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\n" ); document.write( "x = -3+2sqrt(3)
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\n" ); document.write( "Solve for \"y\":
\n" ); document.write( "y = x+1
\n" ); document.write( "y = -2+2sqrt(3)
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\n" ); document.write( "I doubt that is the answer you are looking for
\n" ); document.write( "but that is what your post implies.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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