document.write( "Question 417614: Please answer this problem using systems of linear equations in three variables.\r
\n" ); document.write( "\n" ); document.write( "The sum of the length, width and the height of a rectangular box is 17 cm. Twice the width exceeds the height by by 1 and the sum of the length and the width is shorter than the height by 1 cm. Find the dimensions of the box.
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Algebra.Com's Answer #292376 by htmentor(1343)\"\" \"About 
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l+w+h=17 (1)
\n" ); document.write( "2w=h+1 (2)
\n" ); document.write( "l+w=h-1 (3)
\n" ); document.write( "Substitute the value for l+w from (3) into (1)
\n" ); document.write( "h-1+h=17 -> h=9
\n" ); document.write( "Using (2), we get 2w=10 or w=5
\n" ); document.write( "Use (1) or (3) to get l
\n" ); document.write( "From (3) we have l+5=8 or l=3
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