document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=417638>Question 417638</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the indicated outputs for F(x)= 3x squared -4x<BR>\n" );
document.write( "F (0)=<BR>\n" );
document.write( "f (-1)=<BR>\n" );
document.write( "f (2)= </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #292363 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=292363\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Note: x^2 means x squared\r<BR>\n" );
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document.write( "F(0) = 3(0)^2 - 4(0) = 3(0) - 4(0) = 0 - 0 = 0\r<BR>\n" );
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document.write( "So F(0) = 0\r<BR>\n" );
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document.write( "F(-1) = 3(-1)^2 - 4(-1) = 3(1) - 4(-1) = 3+4 = 7\r<BR>\n" );
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document.write( "So F(-1) = 7\r<BR>\n" );
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document.write( "F(2) = 3(2)^2 - 4(2) = 3(4) - 4(2) = 12-8 = 4\r<BR>\n" );
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document.write( "So F(2) = 4\r<BR>\n" );
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document.write( "Jim </SPAN>\n" );
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