document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=417637>Question 417637</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2/7+4/21+1/3 please help i need to show work also i need to know how to do this problem? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #292362 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=292362\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In order to add fractions, the denominators must all be the same. So let's get all the denominators equal to the LCD 21. \r<BR>\n" );
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document.write( "2/7+4/21+1/3 = (2/7)*(3/3)+4/21+(1/3)*(7/7) = 6/21+4/21+7/21 = (6+4+7)/21 = 17/21\r<BR>\n" );
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document.write( "So 2/7+4/21+1/3 = 17/21\r<BR>\n" );
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document.write( "Jim </SPAN>\n" );
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