document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=417619>Question 417619</A>: <I><SPAN STYLE=\"word-break: break-all;\"> sovle with a compound inequality<BR>\n" );
document.write( "(x+10)(x-2)(x+2)>0<BR>\n" );
document.write( "my answer is -10<x<-2  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #292347 by </B><A HREF=/tutors/aboutme.mpl?userid=Gogonati><B>Gogonati(855)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Gogonati><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Gogonati><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=292347\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (x+10)(x-2)(x+2)>0 The roots for this equation are; x=-10; x=-2; x=2.In this inequality we have three linear factors; x+10; x-2; x+2. We study each of them.<BR>\n" );
document.write( "x+10 is positive for x>-10 and negative for x<-10. <BR>\n" );
document.write( "x+2 is positive for x>-2 and negative for x<-2<BR>\n" );
document.write( "x-2 is positive for x>2 and negative for x<2<BR>\n" );
document.write( "Their product is positive for -10<x<-2 and x>2<BR>\n" );
document.write( "Thus the solution set is R={ x such that: ( -10< x <-2) U (x>2)}. </SPAN>\n" );
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