document.write( "Question 417580: A self-employed contractor nearing retirement made two investments totaling $15,000. In one year, these investments yielded $1023 in simple interest. Part of the money was invested at 6% and the rest at 7.5%. How much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #292326 by stanbon(75887) ![]() You can put this solution on YOUR website! A self-employed contractor nearing retirement made two investments totaling $15,000. In one year, these investments yielded $1023 in simple interest. Part of the money was invested at 6% and the rest at 7.5%. How much was invested at each rate? \n" ); document.write( "-------------------- \n" ); document.write( "Equations: \n" ); document.write( "Quantity: x + y = 15000 \n" ); document.write( "Interest0.06x + 0.075y = 1023 \n" ); document.write( "----- \n" ); document.write( "Multiply thru 1st by 6 \n" ); document.write( "Multiply thru 2nd by 1000 \n" ); document.write( "------ \n" ); document.write( "6x + 6y = 6*15000 \n" ); document.write( "6x + 75y = 1023000 \n" ); document.write( "---------------------------- \n" ); document.write( "Subtract and solve for \"y\": \n" ); document.write( "69y = 933000 \n" ); document.write( "--- \n" ); document.write( "y = $13,521.74 (amt. invested at 7.5% \n" ); document.write( "--- \n" ); document.write( "Solve for \"x\": \n" ); document.write( "15000 - y = $1,478.27 (amt. invested at 6% \n" ); document.write( "======================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=========== \n" ); document.write( " |