document.write( "Question 417466: A woman invested 4 times as much at 5% as she did at 6%. The total amount of interest she earns in 1 year from both accounts is $520. How much did she invest at each rate? \n" ); document.write( "

Algebra.Com's Answer #292252 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"x\"$ = amount invested @ 6%
\n" ); document.write( "given:
\n" ); document.write( " $\"4x\"$ = amount invested @ 5%
\n" ); document.write( "-------------------------
\n" ); document.write( " $\".06x+%2B+.05%2A%284x%29+=+525\"$
\n" ); document.write( " $\".06x+%2B+.2x+=+525\"$
\n" ); document.write( " $\".26x+=+525\"$
\n" ); document.write( " $\"x+=+2019.23\"$
\n" ); document.write( " $\"4x+=+8076.92\"$
\n" ); document.write( "She invested $2019.23 @ 6%
\n" ); document.write( "She invested $8076.92 @ 5%
\n" ); document.write( "check answer:
\n" ); document.write( " $\".06x+%2B+.05%2A%284x%29+=+525\"$
\n" ); document.write( " $\".06%2A2019.23+%2B+.05%2A%288076.92%29+=+525\"$
\n" ); document.write( " $\"+121.15+%2B+403.85+=+525\"$
\n" ); document.write( " $\"+524.996+=+525\"$ (close enough) \n" ); document.write( "

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