document.write( "Question 417424: we are suppose to evaluate
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Algebra.Com's Answer #292231 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\"sin%283%2F4%29%2Api+=+135\" degrees\r
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\n" ); document.write( "\n" ); document.write( "\"135\" deg. lies in the \"2nd\" quadrant\r
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\n" ); document.write( "\n" ); document.write( "little more:\r
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\n" ); document.write( "\n" ); document.write( "It is the \"same\" as \"45+deg\", but a reference angle.\r
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\n" ); document.write( "\n" ); document.write( "\"sin%2845%29=+leg%2Fhyp+=+1%2Fsqrt%282%29=+sqrt%282%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "\"cos%2845%29=1%2Fsqrt%282%29=+sqrt%282%29%2F2\"\r
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\n" ); document.write( "\n" ); document.write( "But in the second quadrant \"highlight%28sine%29\"is\"positive\" and \"highlight%28cosine%29\" is \"negative\"\r
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\n" ); document.write( "\n" ); document.write( "so, \"sin%283%2A+pi%2F4%29+=+1%2Fsqrt%282%29=sqrt%282%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"cos%283+%2Api+%2F4%29+=+-1%2Fsqrt%282%29=-sqrt%282%29%2F2\"}\r
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\n" ); document.write( "\n" ); document.write( "This will summarizes all:\r
\n" ); document.write( "\n" ); document.write( "Quadrant I: 0 to 90 degrees = 0 to p/2 radians\r
\n" ); document.write( "\n" ); document.write( "Quadrant II: 90 to 180 degrees = p/2 to p radians\r
\n" ); document.write( "\n" ); document.write( "Quadrant III: 180 to 270 degrees = p to 3p/2 radians\r
\n" ); document.write( "\n" ); document.write( "Quadrant IV: 270 to 360 degrees = 3p/2 to 2p radians\r
\n" ); document.write( "\n" ); document.write( "where p = 3.14 rounded to 2 decimal places.\r
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