document.write( "Question 417354: solve by factoring 2x^2 -x-3=0 \n" ); document.write( "

Algebra.Com's Answer #292206 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "factoring    
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document.write( "  2x^2 -x-3=0
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document.write( " (2x -3)(x+1)= 0  x = 3/2 and x = -1
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document.write( "Note:SUM of the inner product(-3x) and the outer product(2x) = -x \n" );
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