document.write( "Question 417331: A donation box contains 49 coins consisting of nickels, dimes, and quarters. The number of quarters is two more than twice the number of dimes. The total value of the coins is $3.30. Find the number of nickles, dimes, and quarters. \n" ); document.write( "

Algebra.Com's Answer #292201 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "49 coins. The number of quarters is two more than twice the number of dimes
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document.write( "Let x , (2x+2), [49 -(3x+2)] represent the number of dimes, quarters and nickels
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document.write( "Question states***CENTS makes sense
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document.write( "  10x + 25(2x+2) + 5[49-(3x+2)] = 330
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document.write( "Solving for x
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document.write( "  10x + 50x+ 50 + 245 -15x - 10 = 330
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document.write( "        45x = 45
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document.write( "          x = 1, the number of dimes, 4 Quarters and 44 Nickels\r
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document.write( "CHECKING our Answer***
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document.write( "   10*1 + 25*4 + 5*44 =  110 + 220 = 330 or $3.30 \n" );
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