document.write( "Question 417381: The sum of the digits of a two-digit number is 14. When the digits are reversed, the resulting number is 23 less than two times the original number. What is the original number? \n" ); document.write( "
Algebra.Com's Answer #292189 by mananth(16946)\"\" \"About 
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x-- ten's digit
\n" ); document.write( "y --- unit's digit\r
\n" ); document.write( "\n" ); document.write( "x+y =14........1
\n" ); document.write( "10y+x= 2(10x+y)-23
\n" ); document.write( "10y+x=20x+2y-23
\n" ); document.write( "8y-19x=-23............2\r
\n" ); document.write( "\n" ); document.write( "x+y=14 .............1
\n" ); document.write( "-19x+8y= -23.............2
\n" ); document.write( "
\n" ); document.write( "multiply (1)by -8
\n" ); document.write( "Multiply (2) by 1
\n" ); document.write( "-8x-8y=-112
\n" ); document.write( "-19x+8y= -23
\n" ); document.write( "
\n" ); document.write( "Add the two equations
\n" ); document.write( "-27x=-135
\n" ); document.write( "
\n" ); document.write( "/-27
\n" ); document.write( "
\n" ); document.write( "x=5
\n" ); document.write( "
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "x+y=14
\n" ); document.write( "5+y=14
\n" ); document.write( "y=14-5
\n" ); document.write( "y=9\r
\n" ); document.write( "\n" ); document.write( "Number is 59
\n" ); document.write( " y = 9
\n" ); document.write( " \n" ); document.write( "
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