document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=417374>Question 417374</A>: <I><SPAN STYLE=\"word-break: break-all;\">   the cross section of a drain is a rectangle 30 cm wide  if water 3.5 cm deep flows along the drain at a rate of 22 cm per second how many litres of water will flow through each minute </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #292185 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=292185\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The volume held in 1 cm length = 30*3.25*1= 97.5 cm^3\r<BR>\n" );
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document.write( "the volume held in 22 cms=<BR>\n" );
document.write( "97.5 * 22 =2145 cm^3<BR>\n" );
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document.write( "1 sec flow is 2145 cm^3<BR>\n" );
document.write( "60 seconds the flow will be 2145 * 60 <BR>\n" );
document.write( "=128,700 cm^3\r<BR>\n" );
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document.write( "1cm^3=0.001 liter<BR>\n" );
document.write( "128700 cm^3= 128700*0.001<BR>\n" );
document.write( "=128.7 liters </SPAN>\n" );
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