document.write( "Question 414998: write the equation in standard form of a parabola with a vertex of (-3,6) that goes through (1,-2) \n" ); document.write( "
Algebra.Com's Answer #292172 by lwsshak3(11628)\"\" \"About 
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write the equation in standard form of a parabola with a vertex of (-3,6) that goes through (1,-2)\r
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\n" ); document.write( "\n" ); document.write( "Standard form of the parabola: y=A(x-h)^2+k, with (h,k)= (x,y) coordinates of vertex, and A = coefficient of (x-h)^2. The problem in given case is to find A.\r
\n" ); document.write( "\n" ); document.write( "given parabola:
\n" ); document.write( "y=A(x+3)^2+6
\n" ); document.write( "using given point (1,-2),solve for A
\n" ); document.write( "-2=A(1+3)^2+6
\n" ); document.write( "-2=A(4^2)+6
\n" ); document.write( "-8=16A
\n" ); document.write( "A=-1/2
\n" ); document.write( "Equation of parabola:
\n" ); document.write( "y=-1/2(x+3)^2+6
\n" ); document.write( "The graph below is what the parabola looks like.
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+20%2C+-.5%28x%2B3%29%5E2%2B6%0D%0A%29+\"
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