document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=417178>Question 417178</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangule is 2 cm more than 5 times the width, the perimeter is 196 cm. find the width and length  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #292150 by </B><A HREF=/tutors/aboutme.mpl?userid=jsmallt9><B>jsmallt9(3758)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jsmallt9><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=292150\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the width<BR>\n" );
document.write( "Then the length which is \"2 cm more than 5 times the width\" would be: 2+5x<BR>\n" );
document.write( "The perimeter is is the sum of 2 lengths and 2 widths. So<BR>\n" );
document.write( "196 = 2*x + 2*(2+5x)<BR>\n" );
document.write( "which simplifies to:<BR>\n" );
document.write( "196 = 2x + 4 + 10x<BR>\n" );
document.write( "196 = 12x + 4<BR>\n" );
document.write( "Subtracting 4 from each side:<BR>\n" );
document.write( "192 = 12x<BR>\n" );
document.write( "Dividing both sides by 12:<BR>\n" );
document.write( "16 = x<BR>\n" );
document.write( "Since x was the width, the width is 16. The length is 2+5x. Since x = 16, the length would be 2 + 5(16) = 1 + 80 = 82.<br><BR>\n" );
document.write( "So width = 16cm and length = 82cm. </SPAN>\n" );
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