document.write( "Question 417039: 6=2logx+1/3logy\r
\n" ); document.write( "\n" ); document.write( "solve for x
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Algebra.Com's Answer #292146 by jsmallt9(3758)\"\" \"About 
You can put this solution on YOUR website!
\"6+=+2log%28%28x%29%29+%2B+%281%2F3%29log%28%28y%29%29\"
\n" ); document.write( "Let's start by getting rid of the fraction. Multiplying both sides by 3 we get:
\n" ); document.write( "\"18+=+6log%28%28x%29%29+%2B+log%28%28y%29%29\"
\n" ); document.write( "Next we will subtract log(y):
\n" ); document.write( "\"18+-+log%28%28y%29%29+=+6log%28%28x%29%29\"
\n" ); document.write( "Now we'll divide both sides by 6:
\n" ); document.write( "\"%2818+-+log%28%28y%29%29%29%2F6+=+log%28%28x%29%29\"
\n" ); document.write( "which will simplify to:
\n" ); document.write( "\"3+-+%28log%28%28y%29%29%2F6%29+=+log%28%28x%29%29\"
\n" ); document.write( "And last, we will rewrite the equation in exponential form. In general \"log%28a%2C+%28p%29%29+=+q\" is equivalent to \"p+=+a%5Eq\". Using this pattern on your equation we get:
\n" ); document.write( "\"10%5E%283+-+%28log%28%28y%29%29%2F6%29%29+=+x\"
\n" ); document.write( "(Sometimes expressions like the one above do not display well in your browser. If this is the case. then picture the left side as a 10 with an exponent of \"3+-+%28log%28%28y%29%29%2F6%29\"
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