document.write( "Question 417178: The length of a rectangule is 2 cm more than 5 times the width, the perimeter is 196 cm. find the width and length \n" ); document.write( "

Algebra.Com's Answer #292138 by praseenakos@yahoo.com(507) $\"\"$ $\"About$

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let the width = x\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "length = x + 2\r
\n" ); document.write( "\n" ); document.write( "Perimeter = 196\r
\n" ); document.write( "\n" ); document.write( "2(length+ width ) = 196\r
\n" ); document.write( "\n" ); document.write( " $\"+2%28x%2B2%2Bx%29+=+196\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"+2%282x%2B2%29+=+196\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"+2%282x%2B2%29%2F2+=+196%2F2\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"++2x%2B2++=+98\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"++2x%2B2-2+=+98-2\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"++2x+++=+96\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"++2x%2F2++=+96%2F2\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"++x++=++48\"$ \r
\n" ); document.write( "\n" ); document.write( "width = 48\r
\n" ); document.write( "\n" ); document.write( "so length = 48+2 = 50\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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