document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=417104>Question 417104</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of two numbers is 15. Three times one of the numbers is 11 less then five times the other.Find the number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #292090 by </B><A HREF=/tutors/aboutme.mpl?userid=vanebutterfly01><B>vanebutterfly01(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vanebutterfly01><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=292090\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> lets say X and Y are the \"numbers\" so it will be\r<BR>\n" );
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document.write( "X+Y=15<BR>\n" );
document.write( "3x-5y=11\r<BR>\n" );
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document.write( "so we know that we can multiply so that you able to cancel out the 3x...so <BR>\n" );
document.write( "we mulitply x+y=15 mulitply it by negative 3 so it can get canceled out. <BR>\n" );
document.write( "so the new equation is -3x-3y=45<BR>\n" );
document.write( "so now you can rewrite it as \r<BR>\n" );
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document.write( "-3x-3y=45<BR>\n" );
document.write( " 3x-5y=11<BR>\n" );
document.write( "   -8y=36<BR>\n" );
document.write( "so then <BR>\n" );
document.write( "-8y divided by -8 is just y so then 36/-8 is -4 <BR>\n" );
document.write( "so Y=-4<BR>\n" );
document.write( " </SPAN>\n" );
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