document.write( "Question 417043: if you have 78 90 68 and 83 what do you need to get an average of 80 \n" ); document.write( "
Algebra.Com's Answer #292066 by checkley79(3341)\"\" \"About 
You can put this solution on YOUR website!
I'll assume you mean by one additional test score.
\n" ); document.write( "(78+90+68+83+x)/5=80
\n" ); document.write( "(319+x)/5=80 cross multiply
\n" ); document.write( "319+x=80*5
\n" ); document.write( "319+x=400
\n" ); document.write( "x=400-319
\n" ); document.write( "x=81 ans. for the test score to maintain an 80 average.
\n" ); document.write( "Proof:
\n" ); document.write( "(78+90+68+83+81)/5=80
\n" ); document.write( "400/5=80
\n" ); document.write( "400=400
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