document.write( "Question 417043: if you have 78 90 68 and 83 what do you need to get an average of 80 \n" ); document.write( "
Algebra.Com's Answer #292066 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! I'll assume you mean by one additional test score. \n" ); document.write( "(78+90+68+83+x)/5=80 \n" ); document.write( "(319+x)/5=80 cross multiply \n" ); document.write( "319+x=80*5 \n" ); document.write( "319+x=400 \n" ); document.write( "x=400-319 \n" ); document.write( "x=81 ans. for the test score to maintain an 80 average. \n" ); document.write( "Proof: \n" ); document.write( "(78+90+68+83+81)/5=80 \n" ); document.write( "400/5=80 \n" ); document.write( "400=400 \n" ); document.write( " \n" ); document.write( " |