document.write( "Question 417052: Ok so in algebra today we learned like 2 days ago the QUADRATIC FORMULA...well i just dont understand how to solve it. for ex.
\n" ); document.write( " $\"3x%5E2%2B4x-8=0\"$ \r
\n" ); document.write( "\n" ); document.write( "I dont understand how to do the steps to get the answer\r
\n" ); document.write( "\n" ); document.write( "so i do x=-4+/-=sqrt (4)^2-4(3)(-8)
\n" ); document.write( "then x= +/-+sqrt 16-96/ 2x3
\n" ); document.write( "i dont know where to go from there. \n" ); document.write( "

Algebra.Com's Answer #292062 by checkley79(3341) $\"\"$ $\"About$

You can put this solution on YOUR website!
3x^2+4x-8=0
\n" ); document.write( " $\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"$
\n" ); document.write( "x=(-4+-sqrt[4^2-4*3*-8])/2*3
\n" ); document.write( "x=(-4+-sqrt[16+96])/6
\n" ); document.write( "x=(-4+-sqrt112)/6
\n" ); document.write( "x=(-4+-10.583)/6
\n" ); document.write( "x=(-4+10.583)/6
\n" ); document.write( "x=6.583/6
\n" ); document.write( "x=1.097 ans.
\n" ); document.write( "x=(-4-10.583)/6
\n" ); document.write( "x=-14.853/6
\n" ); document.write( "x=-2.43 ans. \n" ); document.write( "

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