document.write( "Question 416929: Nina has a total of $ 2500 to invest. She puts part of it in an investment that pays 6% per year. The remaining money she puts in an investment that pays 5% per year. At the end of one year she has earned $138.50 in interest. How much money did she put in each of the investments? \n" ); document.write( "
Algebra.Com's Answer #292056 by checkley79(3341)\"\" \"About 
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.06x+.05(2,500-x)=138.50
\n" ); document.write( ".06x+125-.05x=138.50
\n" ); document.write( ".01x=138.50-125
\n" ); document.write( ".01x=13.50
\n" ); document.write( "x=13.50/.01
\n" ); document.write( "x=$1,350 aamount invested @ 6%
\n" ); document.write( "2,500-1,350=$1,150 amount invested @ 5%.
\n" ); document.write( "Proof:
\n" ); document.write( ".06*1,350+.05*1,150=138.50
\n" ); document.write( "81+57.50=138.50
\n" ); document.write( "138.50=138.50
\n" ); document.write( "
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