document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=416975>Question 416975</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve using the substitution method<BR>\n" );
document.write( "x + 4y = 2;  6x + 5y = -12 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #292022 by </B><A HREF=/tutors/aboutme.mpl?userid=Gogonati><B>Gogonati(855)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Gogonati><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Gogonati><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=292022\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solution: From the first linear equation x=2-4y Substitute this value of x in the second equation; 6(2-4y)+5y=-12 This is a first grade equation. Solving it we find out the value of y. 12-24y +5y=-12: -19y=-24; y=24/19 To find out the x value substitute y=24/19 in the first equation; x=2-4(24/19); x=-58/19.<BR>\n" );
document.write( "Answer: the solution for this system linear equations is the ordered pair (-58/19,24/19). </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );