document.write( "Question 416950: Please help with this problem.
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document.write( "1) As a science project, Anwar monitored the content of carbon monoxide outside his house in the city over several days. He found that it reached a maximum of about 30 ppm (parts per million) at 6:00 P.M., and a minimum of 10 ppm at 6:00 A.M.
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document.write( "a) Model the concentration of carbon monoxide, C, in parts per million, as a function of time, t, in hours. Use a sinusoidal function. \n" );
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Algebra.Com's Answer #292015 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Please help with this problem. \n" ); document.write( "1) As a science project, Anwar monitored the content of carbon monoxide outside his house in the city over several days. He found that it reached a maximum of about 30 ppm (parts per million) at 6:00 P.M., and a minimum of 10 ppm at 6:00 A.M. \n" ); document.write( "a) Model the concentration of carbon monoxide, C, in parts per million, as a function of time, t, in hours. Use a sinusoidal function. \n" ); document.write( "---- \n" ); document.write( "amplitude = (30-10)/2 = 10 \n" ); document.write( "----- \n" ); document.write( "Period = 24 hrs \n" ); document.write( "So, (2pi)/b = 24 \n" ); document.write( "b = (1/12)pi \n" ); document.write( "------- \n" ); document.write( "Phase shift = ? \n" ); document.write( "The day begins at 12:00PM which is 6hrs before max. \n" ); document.write( "So, -c/b = 6 hrs \n" ); document.write( "So, -c/[1/12pi] = 6 \n" ); document.write( "-c = (1/2)pi \n" ); document.write( "c = -(pi/2) \n" ); document.write( "===================== \n" ); document.write( "Equation: \n" ); document.write( "y = 10sin[(2pi/9)x-(pi/2)]+20 \n" ); document.write( "---- \n" ); document.write( " \n" ); document.write( "===================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |