document.write( "Question 416652: How do I set this up so I can solve it, it's a word proble.
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document.write( "An anthropologist studying the bones of a prehistoric person finds there is so little remaining Carbon-14 in the bones that instruments cannot measure it. This means there is less than 0.5% of the amount of Carbon-14 the bones would have contained when the person was alive. How long ago did the person die? \n" );
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Algebra.Com's Answer #291874 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! An anthropologist studying the bones of a prehistoric person finds there is so little remaining Carbon-14 in the bones that instruments cannot measure it. \n" ); document.write( "--------------------------------- \n" ); document.write( "This means there is less than 0.5% of the amount of Carbon-14 the bones would have contained when the person was alive. \n" ); document.write( "--------------------- \n" ); document.write( "How long ago did the person die? \n" ); document.write( "--- \n" ); document.write( "Carbon 14 half-life is 5730 years \n" ); document.write( "---- \n" ); document.write( "Equation to use: \n" ); document.write( "A(t) = Ao(1/2)^(t/5730) \n" ); document.write( "0.0005Ao = Ao(1/2)^(t/5730) \n" ); document.write( "----- \n" ); document.write( "(1/2)^(t/5730) = 0.0005 \n" ); document.write( "--- \n" ); document.write( "Take the ln of both sides: \n" ); document.write( "(t/5730)ln(1/2) = ln(0.0005) \n" ); document.write( "--- \n" ); document.write( "t/5730 = 10.9658 \n" ); document.write( "t > 62,833.94 year old \n" ); document.write( "======================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |