document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=416517>Question 416517</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Im taking algebra 1 and I don't understand at all Im stuck on this one problem I just can't solve it and I don't understand how to attempt to get the answer. \r<BR>\n" );
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document.write( "-5x + 3y = 11 \r<BR>\n" );
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document.write( "x - 2y  = 2 \r<BR>\n" );
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document.write( "they want me to solve this problem using the substitution method?? can you please explain this to me \r<BR>\n" );
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document.write( "Thank you  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #291818 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=291818\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x-2y=2 becomes x=2y+2<BR>\n" );
document.write( "sutstitute 2y+2 for x in the other equation.<BR>\n" );
document.write( "-5(2y+2)+3y=11<BR>\n" );
document.write( "-10y-10+3y=11<BR>\n" );
document.write( "combine<BR>\n" );
document.write( "-7y=21<BR>\n" );
document.write( "y=-3<BR>\n" );
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document.write( "use -3 for y<BR>\n" );
document.write( "-5x+3*-3=11<BR>\n" );
document.write( "-5x-9=11<BR>\n" );
document.write( "-5x=20<BR>\n" );
document.write( "x=-4<BR>\n" );
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document.write( "put both values in the other equation for a check.<BR>\n" );
document.write( "-4-2(-3)=2<BR>\n" );
document.write( "-4+6=2 </SPAN>\n" );
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