document.write( "Question 416476: The sum of the squares of two consecutive positive even integers is one hundred sixty-four. Find the two integers.
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Algebra.Com's Answer #291774 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "Let x and (x+2) represent the two consecutive 'positive' even integers 
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document.write( "Question states***
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document.write( " x^2 + (x+2)^2 = 164
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document.write( "Solving for x
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document.write( " x^2 + x^2 + 4x + 4 = 164
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document.write( "   2x^2 + 4x - 160 = 0
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document.write( "    x^2 + 2x - 80 = 0
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document.write( "factoring
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document.write( "  (x+10)(x-8)= 0  Note:SUM of the inner product(10x) and the outer product(-8x)=2x  
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document.write( "  (x+10)=0  x = -10  Tossing out negative solution for 'positive integer'
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document.write( "  (x-8)= 0  x = 8   the two consecutive 'positive' even integers are 8,10\r
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document.write( "CHECKING our Answer***
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document.write( "  64 + 100 = 164 \n" );
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