document.write( "Question 416428: How much pure acid should be mixed with 2 gallons of a 40% acid solution in order to get an 80%acid solution
\n" );
document.write( " \n" );
document.write( "
Algebra.Com's Answer #291754 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! How much pure acid should be mixed with 2 gallons of a 40% acid solution in order to get an 80% acid solution \n" ); document.write( "------------------- \n" ); document.write( "Equation: \n" ); document.write( "acid + acid = acid \n" ); document.write( "0.40*2 + 1*x = 0.80(2+x) \n" ); document.write( "---- \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "40*2 + 100x = 80*2 + 80x \n" ); document.write( "20x = 40*2 \n" ); document.write( "x = 4 gallons (amt. of pure acid needed) \n" ); document.write( "=============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=============== \n" ); document.write( " |