document.write( "Question 416392: Find three consecutive odd integers whose sum is 141 \n" ); document.write( "

Algebra.Com's Answer #291735 by poliphob3.14(115) $\"\"$ $\"About$

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Solution: Three consecutive ood integers are: x, x+2, x+4. Since their sum is 141 we write the equation: x+x+2+x+4=141, 3x+6=141, 3x=135, x=45. The first ood number is 45, the second 45+2=47 and the third 47+2=49.
\n" ); document.write( "Proof: 45+47+49=141. \n" ); document.write( "

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