document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=416151>Question 416151</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you solve this problem. And please explain because I am having trouble. \r<BR>\n" );
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document.write( "log x = 2 log a 3 + log a 5\r<BR>\n" );
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document.write( "To do this I just first switched it so that log x = 2 would be at the end instead of the beginning. <BR>\n" );
document.write( "And then I used the first law of logarithm and got this:<BR>\n" );
document.write( "2loga^15=logaX\r<BR>\n" );
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document.write( "Now what? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #291698 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=291698\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log x = 2 log a 3 + log a 5 <BR>\n" );
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document.write( "Assuming the problem is:<BR>\n" );
document.write( "log(x) = 2log(a^3) + log(a^5)<BR>\n" );
document.write( "which is<BR>\n" );
document.write( "log(x) = 3*2log(a) + 5log(a)<BR>\n" );
document.write( "log(x) = 6log(a) + 5log(a)<BR>\n" );
document.write( "log(x) = 11*log(a)<BR>\n" );
document.write( "which is<BR>\n" );
document.write( "log(x) = log(a^11)<BR>\n" );
document.write( "therefore<BR>\n" );
document.write( "x = a^11<BR>\n" );
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document.write( " </SPAN>\n" );
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