document.write( "Question 416168: a river boat tour begins by going 60 miles upstream against a 5 mph current. Then the boat turns around and returns with the current. What still-water speed should the captain use to complete the tour in 5 hours? \n" ); document.write( "
Algebra.Com's Answer #291629 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let speed in still water =x mph \n" ); document.write( "current speed 4 mph \n" ); document.write( " \n" ); document.write( "upstream speed = x-4 \n" ); document.write( "downstream speed = x+4 \n" ); document.write( " \n" ); document.write( "Distance= 60 miles \n" ); document.write( " \n" ); document.write( "Time upstream + time downstream = 5 hours \n" ); document.write( "t=d/r \n" ); document.write( "60/(x+4)+60(x-4)=5 \n" ); document.write( "LCD =(x -4)(x+4) \n" ); document.write( "60*(x-4)+60(x+4)=5 \n" ); document.write( "60x-240 +60x+240=5(X^2-16) \n" ); document.write( "120x=5X^2-80 \n" ); document.write( "5X^2-120x-80 \n" ); document.write( "a= 5, b= -120, c=-80 \n" ); document.write( "b^2-4ac= 12800 \n" ); document.write( " \n" ); document.write( "x1=23.3 mph\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "=0.69 -- not practical \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |