document.write( "Question 416168: a river boat tour begins by going 60 miles upstream against a 5 mph current. Then the boat turns around and returns with the current. What still-water speed should the captain use to complete the tour in 5 hours? \n" ); document.write( "
Algebra.Com's Answer #291629 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
let speed in still water =x mph
\n" ); document.write( "current speed 4 mph
\n" ); document.write( "
\n" ); document.write( "upstream speed = x-4
\n" ); document.write( "downstream speed = x+4
\n" ); document.write( "
\n" ); document.write( "Distance= 60 miles
\n" ); document.write( "
\n" ); document.write( "Time upstream + time downstream = 5 hours
\n" ); document.write( "t=d/r
\n" ); document.write( "60/(x+4)+60(x-4)=5
\n" ); document.write( "LCD =(x -4)(x+4)
\n" ); document.write( "60*(x-4)+60(x+4)=5
\n" ); document.write( "60x-240 +60x+240=5(X^2-16)
\n" ); document.write( "120x=5X^2-80
\n" ); document.write( "5X^2-120x-80
\n" ); document.write( "a= 5, b= -120, c=-80
\n" ); document.write( "b^2-4ac= 12800
\n" ); document.write( "\"x1=%28120%2Bsqrt%2812800%29%29%2F%2810%29\"
\n" ); document.write( "x1=23.3 mph\r
\n" ); document.write( "\n" ); document.write( "\"x2=%28120-sqrt%2812800%29%29%2F%2810%29\"
\n" ); document.write( "=0.69 -- not practical
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" );