document.write( "Question 416132: Factor the expression correctly 32b^2 - 20b - 3. i dont know how to factor it if all the numbers have no GCF. Can u please help me how to factor it. \n" ); document.write( "
Algebra.Com's Answer #291604 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Looking at the expression \"32b%5E2-20b-3\", we can see that the first coefficient is \"32\", the second coefficient is \"-20\", and the last term is \"-3\".\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient \"32\" by the last term \"-3\" to get \"%2832%29%28-3%29=-96\".\r
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\n" ); document.write( "\n" ); document.write( "Now the question is: what two whole numbers multiply to \"-96\" (the previous product) and add to the second coefficient \"-20\"?\r
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\n" ); document.write( "\n" ); document.write( "To find these two numbers, we need to list all of the factors of \"-96\" (the previous product).\r
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\n" ); document.write( "\n" ); document.write( "Factors of \"-96\":\r
\n" ); document.write( "\n" ); document.write( "1,2,3,4,6,8,12,16,24,32,48,96\r
\n" ); document.write( "\n" ); document.write( "-1,-2,-3,-4,-6,-8,-12,-16,-24,-32,-48,-96\r
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\n" ); document.write( "\n" ); document.write( "Note: list the negative of each factor. This will allow us to find all possible combinations.\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to \"-96\".\r
\n" ); document.write( "\n" ); document.write( "1*(-96) = -96
\n" ); document.write( "2*(-48) = -96
\n" ); document.write( "3*(-32) = -96
\n" ); document.write( "4*(-24) = -96
\n" ); document.write( "6*(-16) = -96
\n" ); document.write( "8*(-12) = -96
\n" ); document.write( "(-1)*(96) = -96
\n" ); document.write( "(-2)*(48) = -96
\n" ); document.write( "(-3)*(32) = -96
\n" ); document.write( "(-4)*(24) = -96
\n" ); document.write( "(-6)*(16) = -96
\n" ); document.write( "(-8)*(12) = -96\r
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\n" ); document.write( "\n" ); document.write( "Now let's add up each pair of factors to see if one pair adds to the middle coefficient \"-20\":\r
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First NumberSecond NumberSum
1-961+(-96)=-95
2-482+(-48)=-46
3-323+(-32)=-29
4-244+(-24)=-20
6-166+(-16)=-10
8-128+(-12)=-4
-196-1+96=95
-248-2+48=46
-332-3+32=29
-424-4+24=20
-616-6+16=10
-812-8+12=4
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\n" ); document.write( "\n" ); document.write( "From the table, we can see that the two numbers \"4\" and \"-24\" add to \"-20\" (the middle coefficient).\r
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\n" ); document.write( "\n" ); document.write( "So the two numbers \"4\" and \"-24\" both multiply to \"-96\" and add to \"-20\"\r
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\n" ); document.write( "\n" ); document.write( "Now replace the middle term \"-20b\" with \"4b-24b\". Remember, \"4\" and \"-24\" add to \"-20\". So this shows us that \"4b-24b=-20b\".\r
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\n" ); document.write( "\n" ); document.write( "\"32b%5E2%2Bhighlight%284b-24b%29-3\" Replace the second term \"-20b\" with \"4b-24b\".\r
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\n" ); document.write( "\n" ); document.write( "\"%2832b%5E2%2B4b%29%2B%28-24b-3%29\" Group the terms into two pairs.\r
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\n" ); document.write( "\n" ); document.write( "\"4b%288b%2B1%29%2B%28-24b-3%29\" Factor out the GCF \"4b\" from the first group.\r
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\n" ); document.write( "\n" ); document.write( "\"4b%288b%2B1%29-3%288b%2B1%29\" Factor out \"3\" from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.\r
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\n" ); document.write( "\n" ); document.write( "\"%284b-3%29%288b%2B1%29\" Combine like terms. Or factor out the common term \"8b%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"32b%5E2-20b-3\" factors to \"%284b-3%29%288b%2B1%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"32b%5E2-20b-3=%284b-3%29%288b%2B1%29\".\r
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\n" ); document.write( "\n" ); document.write( "Note: you can check the answer by expanding \"%284b-3%29%288b%2B1%29\" to get \"32b%5E2-20b-3\" or by graphing the original expression and the answer (the two graphs should be identical).\r
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\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
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\n" ); document.write( "\n" ); document.write( "Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you\r
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