document.write( "Question 416006: cot^2y(sec^2y-1)=1 \n" ); document.write( "
Algebra.Com's Answer #291567 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "cot^2y(sec^2y-1)=1\r
\n" ); document.write( "\n" ); document.write( ".use identites cot^2y = 1/tan^2y and sec^2y-1 = tan^2y\r
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\n" ); document.write( "\n" ); document.write( "cot^2y(sec^2y-1) = (1/tan^2y)(tan^2y) <--The tan^2y cancels out\r
\n" ); document.write( "\n" ); document.write( "cot^2y(sec^2y-1)= 1
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